© 2002 by Karl Hahn
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Step 1: Draw the diagram. That diagram is shown to the right.

Step 2: Bisect the angle made by the two equal sides.
Step 3: Label the various lengths. You can see that shown as well in the diagram.
Step 4: Write the equation that relates x, s, and P. This is also shown in the diagram. The sum of all the lengths around the triangle must equal P.
Step 5: Write the equation for the triangle's height. Again, that is shown in the diagram, and is derived from the Pythagorean formula
Step 6: Write the area equation. That is one half base times height, and
as you can see, the base is 2x.
1
A = |
_______
(2x)h = x √s2 - x2
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Step 7: Substitute for s. If, according to the perimeter equation, 2x + 2s = P, then s = P/2 - x. Substituting for s into the area equation and then doing a little algebra:
_______________ _________
A = x √(P/2 - x)2 - x2 = x √P2/4 - Px
Step 8: Find the derivative of the area equation. From the above, take the derivative with respect to x. Since the expression for A as a function of x is a product, you will have to use the product rule to find the derivative. Remember that P is a constant:
dA _________ Px= √P2/4 - Px -_________dx 2√P2/4 - Px
Step 9: Set the derivative to zero and solve for x. Once you replace dA/dx with zero, you can multiply through by the radical expression to get
P2 Px P2
0 = |
3Px |
0 = P - 6xor
P
x =
6
Here's the diagram again. Can you see how the
above equation makes it so that the isosceles triangle that maximizes area is equilateral?
Clearly the base is 2x, which must be one third of P. The other two
thirds of P is accounted for by the two remaining sides, each of which are
length, s. Hence s = 2x = P/3. And finally
_______ ____________
h = √s2 - x2 = √P2/9 - P2/36 =
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_ √3P |