Answer to Exercise 11.4-4© 2001 by Karl Hahn |
|
Step 1: Choosing your parts is done for you in the statement of the problem. It is
| b) | u = x |
and | dv |
Step 2: What is v? Just integrate dv/dt, which is done for you in the statement of the problem as well (although you would have needed another round of integration by parts at this step to determine v if this integral weren't already given).
v = |
x e-x dx = |
-x e-x - e-x + C |
Plug what you have for u and v into equation 11.4-6a, then click here to see what you get.
You should have
-x2 e-x - x e-x + C - |
-x e-x - e-x |
du |
x2 e-x dx |
or perhaps you cancelled a few minus signs and got
-x2 e-x - x e-x + C + |
x e-x + e-x |
du |
x2 e-x dx |
Step 3: What is du/dx? Just take the derivative of u = x. And since you've seen this one a bunch of times already, I'm not going to make you click for it.
duwhich simplifies things a bit. Now you have= 1 dx
-x2 e-x - x e-x + C + |
(x e-x + e-x) dx = |
x2 e-x dx |
Step 4: Do the remaining integral. It is an integral of a sum, so you can apply equation 11.2-13b to it. That turns it into
-x2 e-x - x e-x + C + |
x e-x dx + |
e-x dx = |
x2 e-x dx |
You already can figure the second integral from the table.
e-x dx = -ex + C |
and the first one was given in the problem
x e-x dx = |
-x e-x - e-x + C |
So just substitute those expressions in, gather like terms, and then check to make sure you got the same thing as we got when we did it in the text.
You can email me by clicking this button: