Solving for Coefficients in Partial Fractions Example© 2001 by Karl Hahn |
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Here is the procedure for solving the linear equations in the example for A, B, and C by the method of Gaussian elimination. Each procedure tells you how to get from the current set of equations to the next set of equations.
| Equations | Procedure | |
A + B = 1
-2A + 3B + C = -3
A + 3C = 46
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Add 2 times first equation to second equation. Subtract 17 times first equation from third equation. | |
A + B = 1
5B + C = -1
-17B + 3C = 29
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Multiply third equation by 5 | |
A + B = 1
5B + C = -1
-85B + 15C = 145
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Add 17 times second equation to third equation. | |
A + B = 1
5B + C = -1
32C = 128
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Divide 32 out of third equation | |
A + B = 1
5B + C = -1
C = 4
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Subtract third equation from second equation. | |
A + B = 1
5B = -5
C = 4
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Divide 5 out of second equation and subtract the result from the first equation | |
A = 2
B = -1
C = 4
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Done. | |
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