Solving for Coefficients in Partial Fractions Example© 2001 by Karl Hahn |
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Here is the procedure for solving the linear equations in the example for A, B, and C by the method of Gaussian elimination. Each procedure tells you how to get from the current set of equations to the next set of equations.
| Equations | Procedure | |
A + B + C = 1
-5A - 2B - C = 4
6A - 3B - 2C = -33
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Add 5 times first equation to second equation. Subtract 6 times first equation from third equation. | |
A + B + C = 1
3B + 4C = 9
-9B - 8C = -39
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Add 3 times second equation to third equation. | |
A + B + C = 1
3B + 4C = 9
4C = -12
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Subtract third equation from second equation. | |
A + B + C = 1
3B = 21
4C = -12
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Subtract one third of second equation from first equation. | |
A + C = -6
3B = 21
4C = -12
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Subtract one quarter of third equation from first equation. | |
A = -3
3B = 21
4C = -12
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Divide constants out of second and third equations to get solution. | |
A = -3
B = 7
C = -3
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Done. | |
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